To calculate the molality, we need to know the number of moles of NaOH and the mass of water in kilograms.
The molar mass of NaOH is 39.9971 g/mol. So, 2 moles of NaOH is 2 x 39.9971 g = 79.9942 g.
The mass of water is 10Kg = 10,000 g.
Therefore, the molality of the solution is:
$$Molality = \frac{Moles\ of\ Solute}{Mass\ of\ Solvent\ (in\ Kg)}$$
$$Molality = \frac{2 \text{ moles}}{10 \text{ kg}} = 0.2 \text{ m}$$
