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  • Instantaneous Velocity of a Falling Object: A 2-Second Calculation
    Here's how to determine the instantaneous speed of an object dropped in a vacuum 2 seconds after release:

    Understanding the Concepts

    * Free Fall: In a vacuum, an object falls freely under the influence of gravity alone. No air resistance affects its motion.

    * Acceleration due to Gravity (g): On Earth, the acceleration due to gravity is approximately 9.8 m/s². This means an object's velocity increases by 9.8 meters per second every second it falls.

    * Initial Velocity: Since the object is dropped, its initial velocity (v₀) is 0 m/s.

    The Formula

    We can use the following equation from kinematics:

    * v = v₀ + at

    Where:

    * v = final velocity (instantaneous speed)

    * v₀ = initial velocity

    * a = acceleration due to gravity (g = 9.8 m/s²)

    * t = time

    Calculation

    1. Plug in the values:

    * v = 0 + (9.8 m/s²)(2 s)

    2. Solve for v:

    * v = 19.6 m/s

    Answer: The instantaneous speed of the object 2 seconds after being dropped in a vacuum is 19.6 m/s.

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