1. Find the molar mass of lithium fluoride (LiF):
* Lithium (Li) has a molar mass of 6.941 g/mol.
* Fluorine (F) has a molar mass of 18.998 g/mol.
* Molar mass of LiF = 6.941 g/mol + 18.998 g/mol = 25.939 g/mol
2. Calculate the number of moles of LiF:
* Moles of LiF = (mass of LiF) / (molar mass of LiF)
* Moles of LiF = 52 g / 25.939 g/mol = 2.005 mol
3. Calculate the molarity (M):
* Molarity (M) = (moles of solute) / (volume of solution in liters)
* Molarity (M) = 2.005 mol / 1.5 L = 1.337 M
Therefore, the molarity of the lithium fluoride solution is 1.337 M.
