1. Balanced Chemical Equation:
The balanced chemical equation for this reaction is:
2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O
This tells us that 2 moles of NaOH react with 1 mole of H₂SO₄.
2. We need to know the concentration of the sulfuric acid. You provided "17 sulfuric acid," but that's not a standard unit. Do you mean:
* 17 grams of sulfuric acid?
* 17 mL of sulfuric acid? (We'd need the concentration, e.g., 17 mL of 1 M sulfuric acid)
* 17 moles of sulfuric acid?
Let's assume you meant 17 grams of sulfuric acid.
3. Convert grams of H₂SO₄ to moles:
* Find the molar mass of H₂SO₄: (2 x 1.01 g/mol) + (32.07 g/mol) + (4 x 16.00 g/mol) = 98.08 g/mol
* Divide the mass of H₂SO₄ by its molar mass: 17 g / 98.08 g/mol = 0.173 moles H₂SO₄
4. Calculate moles of NaOH:
* Use the mole ratio from the balanced equation: 2 moles NaOH : 1 mole H₂SO₄
* Multiply the moles of H₂SO₄ by the mole ratio: 0.173 moles H₂SO₄ * (2 moles NaOH / 1 mole H₂SO₄) = 0.346 moles NaOH
Therefore, approximately 0.346 moles of sodium hydroxide will react with 17 grams of sulfuric acid.
Important Note: Always double-check the units and make sure you have the correct information before doing any calculations.
