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  • Sodium Content in Sodium Carbonate (Na₂CO₃): A Step-by-Step Calculation
    Here's how to solve this problem:

    1. Determine the molar mass of sodium carbonate (Na₂CO₃):

    * Na: 22.99 g/mol (x 2 since there are 2 sodium atoms) = 45.98 g/mol

    * C: 12.01 g/mol

    * O: 16.00 g/mol (x 3) = 48.00 g/mol

    Total molar mass of Na₂CO₃ = 45.98 + 12.01 + 48.00 = 105.99 g/mol

    2. Calculate the mass of sodium in 1 mole of Na₂CO₃:

    * Mass of sodium in 1 mole of Na₂CO₃ = (45.98 g/mol Na) / (105.99 g/mol Na₂CO₃) = 0.434 g Na/g Na₂CO₃

    3. Calculate the mass of sodium in 3 moles of Na₂CO₃:

    * Mass of sodium in 3 moles of Na₂CO₃ = 0.434 g Na/g Na₂CO₃ x 3 moles Na₂CO₃ x 105.99 g Na₂CO₃/mol Na₂CO₃ = 138 g Na

    Therefore, there are approximately 138 grams of sodium in 3 moles of sodium carbonate.

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