1. Write the balanced chemical equation:

CuCO₃(s) → CuO(s) + CO₂(g)

2. Calculate the molar masses:

* CuCO₃: 63.55 (Cu) + 12.01 (C) + 3 * 16.00 (O) = 123.56 g/mol

* CuO: 63.55 (Cu) + 16.00 (O) = 79.55 g/mol

3. Determine the mole ratio:

From the balanced equation, 1 mole of CuCO₃ produces 1 mole of CuO.

4. Calculate the moles of CuCO₃:

Moles of CuCO₃ = mass / molar mass = 12.5 g / 123.56 g/mol = 0.101 mol

5. Calculate the moles of CuO:

Since the mole ratio is 1:1, 0.101 moles of CuCO₃ will produce 0.101 moles of CuO.

6. Calculate the mass of CuO:

Mass of CuO = moles * molar mass = 0.101 mol * 79.55 g/mol = 8.04 g

Therefore, 8.04 grams of CuO will be obtained by heating 12.5 grams of copper carbonate.