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  • Determine the Empirical Formula: Silicon and Chlorine Compound
    Here's how to determine the formula of the substance:

    1. Determine the moles of each element:

    * Silicon (Si):

    - Molar mass of Si = 28.09 g/mol

    - Moles of Si = (6 g) / (28.09 g/mol) = 0.214 mol

    * Chlorine (Cl):

    - Molar mass of Cl = 35.45 g/mol

    - Moles of Cl = (2.5 g) / (35.45 g/mol) = 0.0706 mol

    2. Find the mole ratio:

    * Divide the number of moles of each element by the smallest number of moles:

    - Si: 0.214 mol / 0.0706 mol ≈ 3

    - Cl: 0.0706 mol / 0.0706 mol ≈ 1

    3. Determine the empirical formula:

    * The mole ratio gives us the empirical formula: Si₃Cl

    4. Calculate the empirical formula mass:

    * (3 x 28.09 g/mol) + (1 x 35.45 g/mol) = 123.72 g/mol

    5. Determine the molecular formula:

    * Divide the given molecular mass by the empirical formula mass:

    - 378 g/mol / 123.72 g/mol ≈ 3

    * Multiply the subscripts in the empirical formula by this factor:

    - Si₃Cl x 3 = Si₉Cl₃

    Therefore, the molecular formula of the substance is Si₉Cl₃.

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