1. Find the molar mass of Al₂O₃:
* Aluminum (Al) has a molar mass of 26.98 g/mol.
* Oxygen (O) has a molar mass of 16.00 g/mol.
* Al₂O₃ has two aluminum atoms and three oxygen atoms: (2 * 26.98 g/mol) + (3 * 16.00 g/mol) = 101.96 g/mol
2. Use the formula:
* moles = mass / molar mass
3. Calculate the moles:
* moles = 12.75 g / 101.96 g/mol
* moles ≈ 0.125 mol
Therefore, there are approximately 0.125 moles of aluminum oxide in 12.75 g.
