The balanced chemical equation for the reaction between HCl and KOH is:

```

HCl + KOH → KCl + H2O

```

The stoichiometry of the reaction shows that 1 mole of HCl reacts with 1 mole of KOH. Therefore, the number of moles of HCl required to neutralize 25.0 ml of 1.00M KOH is:

```

moles of HCl = (25.0 ml / 1000) * 1.00 M = 0.0250 mol

```

The concentration of the HCl solution is 0.45M, so the volume of HCl required to provide 0.0250 mol of HCl is:

```

volume of HCl = (0.0250 mol / 0.45 M) * 1000 = 55.6 ml

```

Therefore, 55.6 ml of 0.45M HCl is required to neutralize 25.0 ml of 1.00M KOH.