The reaction between \(Na_2Cr_2O_7\) and \(NaOH\) produces sodium chromate \( (Na_2CrO_4) \) and water \( (H_2O) \). The balanced chemical equation for this reaction is:

\(Na_2Cr_2O_7 + 2NaOH → 2Na_2CrO_4 + H_2O\)

In this reaction, \(Na_2Cr_2O_7\), also known as sodium dichromate, acts as an oxidizing agent, while \(NaOH\), sodium hydroxide, serves as a base. The reaction involves the transfer of electrons from the \(Cr(VI)\) in the dichromate ion to the \(OH^{-}\) ions from the sodium hydroxide, resulting in the formation of \(Cr(III)\) in the chromate ion.