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  • Calculating the Altitude Where Object Weight Halves: A Physics Explanation
    Here's how to figure out the height at which an object's weight becomes half its weight on Earth:

    Understanding Gravity and Weight

    * Gravity: Gravity is the force of attraction between any two objects with mass. The more massive the objects, the stronger the gravitational force.

    * Weight: Weight is the force of gravity acting on an object's mass. It's calculated using the formula: Weight (W) = Mass (m) * Acceleration due to gravity (g)

    Key Concepts

    * Inverse Square Law: The force of gravity decreases with the square of the distance between the centers of the objects. This means if you double the distance, the force becomes four times weaker.

    * Earth's Radius: The Earth's average radius is approximately 6,371 kilometers (3,959 miles).

    Calculations

    1. Set up the problem: We want to find the height (h) where the weight (W') is half the weight on Earth (W):

    * W' = 1/2 * W

    2. Apply the inverse square law: Since weight is directly proportional to the force of gravity, the weight at height 'h' is inversely proportional to the square of the distance from the Earth's center:

    * W' / W = (R / (R + h))^2

    * Where R is the Earth's radius.

    3. Substitute and solve for h:

    * (1/2 * W) / W = (R / (R + h))^2

    * 1/2 = (R / (R + h))^2

    * √(1/2) = R / (R + h)

    * (R + h) = R / √(1/2)

    * h = R / √(1/2) - R

    * h ≈ 0.414 * R

    4. Plug in Earth's radius:

    * h ≈ 0.414 * 6,371 km

    * h ≈ 2640 km (approximately)

    Answer

    An object's weight would be half its weight on Earth at a height of approximately 2640 kilometers above the Earth's surface.

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