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  • Calculating Net Force and Acceleration with Multiple Forces
    Here's how to solve this problem:

    1. Understand the Forces

    * F1: 20 N acting at 0 degrees (horizontal direction)

    * F2: 15 N acting at 60 degrees (rotated upward from F1)

    2. Resolve Forces into Components

    * F1:

    * Horizontal component (F1x) = 20 N * cos(0°) = 20 N

    * Vertical component (F1y) = 20 N * sin(0°) = 0 N

    * F2:

    * Horizontal component (F2x) = 15 N * cos(60°) = 7.5 N

    * Vertical component (F2y) = 15 N * sin(60°) = 13 N (approximately)

    3. Calculate Net Force

    * Horizontal: F1x + F2x = 20 N + 7.5 N = 27.5 N

    * Vertical: F1y + F2y = 0 N + 13 N = 13 N

    * Resultant Force: To find the magnitude of the resultant force (the net force), use the Pythagorean theorem:

    * Resultant Force (F) = √(27.5² + 13²) ≈ 30.4 N

    4. Calculate Acceleration

    * Newton's Second Law: F = ma (Force equals mass times acceleration)

    * Acceleration (a): a = F/m = 30.4 N / 8 kg ≈ 3.8 m/s²

    Therefore, the acceleration of the 8 kg mass is approximately 3.8 m/s².

    Important Note: The direction of the acceleration is the same as the direction of the resultant force. You can find the angle of the acceleration relative to the horizontal using trigonometry (arctan(13/27.5)).

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