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  • Mastering Molarity: A Step‑by‑Step Guide to Calculating Molar Concentration

    By Chris Deziel
    Updated Aug 30, 2022

    A solution is a homogeneous mixture where a solute is dispersed within a solvent. In most everyday solutions, water serves as the solvent, and the solute determines the solution’s properties. Chemists need a precise way to describe solute concentration, and the most widely used unit is molarity (M), defined as the number of moles of solute per liter of solution.

    What Is a Mole?

    The mole is a foundational measurement in chemistry, anchored by Avogadro’s number (6.022 × 1023 atoms or molecules). One mole of any substance has a mass, in grams, equal to its molar mass (the atomic or molecular weight in atomic mass units). For example, hydrogen’s atomic mass is 1.008 amu, so one mole of hydrogen weighs 1.008 grams.

    To determine the molar mass of a compound, add the atomic masses of all atoms in its formula (found on the periodic table). Once you have the molar mass, you can convert a weighed sample to moles by dividing its mass by the molar mass.

    Example: Sodium hydroxide (NaOH)
    Na (22.990 g/mol), O (15.999 g/mol), H (1.008 g/mol). Molar mass = 22.990 + 15.999 + 1.008 ≈ 40.0 g/mol. A 32‑gram sample contains 32 g ÷ 40.0 g/mol ≈ 0.80 moles.

    How to Calculate Molarity

    With the moles of solute known, you need the solution’s volume in liters. If you measure volume in another unit, convert it using:

    • 1 liter = 0.001 m3 = 1,000 mL = 0.264 US gallons = 33.81 fluid ounces

    Molarity (M) = moles of solute ÷ liters of solution.

    Illustrative Example: Salt in Water

    Calculate the molarity of a solution prepared by dissolving 12 g of sodium chloride (NaCl) in 20 oz of water.

    1. Moles of NaCl

    Na (23.0 g/mol) + Cl (35.5 g/mol) = 58.5 g/mol. Moles = 12 g ÷ 58.5 g/mol ≈ 0.205 moles.

    2. Convert Volume to Liters

    20 oz ÷ 33.81 oz/L ≈ 0.592 L.

    3. Compute Molarity

    0.205 moles ÷ 0.592 L ≈ 0.35 M.

    Thus, the resulting solution has a molarity of roughly 0.35 M.

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