1. Balanced Chemical Equation:

The reaction for the decomposition of potassium chlorate (KClO₃) is:

2 KClO₃ → 2 KCl + 3 O₂

2. Mole Ratio:

From the balanced equation, we see that 2 moles of KClO₃ produce 3 moles of O₂.

3. Calculate Moles of O₂:

* Use the mole ratio to find the moles of O₂ produced:

(5.00 x 10⁻² moles KClO₃) * (3 moles O₂ / 2 moles KClO₃) = 7.50 x 10⁻² moles O₂

4. Convert Moles to Volume (Assuming STP):

* At Standard Temperature and Pressure (STP), 1 mole of any gas occupies 22.4 L.

* Calculate the volume of O₂:

(7.50 x 10⁻² moles O₂) * (22.4 L/mole) = 1.68 L O₂

Therefore, 5.00 x 10⁻² moles of KClO₃ can produce 1.68 L of O₂ at STP.