1. Find the molar mass of AgNO3:
* Ag (Silver): 107.87 g/mol
* N (Nitrogen): 14.01 g/mol
* O (Oxygen): 16.00 g/mol (x3 for three oxygen atoms)
Molar mass of AgNO3 = 107.87 + 14.01 + (16.00 x 3) = 169.88 g/mol
2. Calculate the number of moles of AgNO3:
* Moles = mass / molar mass
* Moles = 147 g / 169.88 g/mol
* Moles ≈ 0.865 mol
3. Convert moles to formula units:
* Use Avogadro's number (6.022 x 10^23 formula units/mol)
* Formula units = moles x Avogadro's number
* Formula units ≈ 0.865 mol x 6.022 x 10^23 formula units/mol
* Formula units ≈ 5.21 x 10^23 formula units
Therefore, there are approximately 5.21 x 10^23 formula units of AgNO3 in 147g of the compound.
