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  • Limiting Reagent Calculation: MgCl₂ + 2KOH Reaction
    Here's how to determine the limiting reagent:

    1. Balanced Chemical Equation:

    The balanced chemical equation is:

    MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

    2. Mole Ratio:

    The equation shows that 1 mole of MgCl₂ reacts with 2 moles of KOH.

    3. Calculate Moles of KOH Needed:

    Since you have 6 moles of MgCl₂, you'll need 6 moles * 2 = 12 moles of KOH to react completely.

    4. Determine the Limiting Reagent:

    * If you have less than 12 moles of KOH: KOH is the limiting reagent, as you don't have enough to react with all of the MgCl₂.

    * If you have 12 moles or more of KOH: MgCl₂ is the limiting reagent because you have enough KOH to react with all of the MgCl₂.

    Conclusion:

    You need to provide the amount of KOH (in moles) to determine the limiting reagent.

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