1. Identify the Limiting Reactant

* The limiting reactant is the reactant that gets used up first and determines the maximum amount of product that can be formed.

* To find the limiting reactant, we need to compare the mole ratios of the reactants to the stoichiometry of the balanced equation.

* The balanced equation shows the mole ratio: 1 mole of MgCl₂ reacts with 2 moles of KOH.

* We have 3 moles of MgCl₂ and 4 moles of KOH.

* To find the limiting reactant, we can calculate how many moles of KOH are needed to react completely with 3 moles of MgCl₂:

* (3 moles MgCl₂) * (2 moles KOH / 1 mole MgCl₂) = 6 moles KOH needed.

* Since we only have 4 moles of KOH, it is the limiting reactant.

2. Calculate the Amount of Mg(OH)₂ Produced

* Use the mole ratio from the balanced equation to calculate the moles of Mg(OH)₂ produced.

* The ratio is: 2 moles of KOH produce 1 mole of Mg(OH)₂.

* Calculate the moles of Mg(OH)₂:

* (4 moles KOH) * (1 mole Mg(OH)₂ / 2 moles KOH) = 2 moles Mg(OH)₂

Conclusion

Because KOH is the limiting reactant, only 2 moles of Mg(OH)₂ can be produced in this reaction.