1. Identify the elements and their atomic masses:
* Silver (Ag): 107.87 g/mol
* Nitrogen (N): 14.01 g/mol
* Oxygen (O): 16.00 g/mol
2. Multiply the atomic mass of each element by its subscript in the formula:
* Ag: 107.87 g/mol * 1 = 107.87 g/mol
* N: 14.01 g/mol * 1 = 14.01 g/mol
* O: 16.00 g/mol * 3 = 48.00 g/mol
3. Add the results together to get the formula mass:
107.87 g/mol + 14.01 g/mol + 48.00 g/mol = 169.88 g/mol
Therefore, the formula mass of silver nitrate (AgNO₃) is 169.88 g/mol.
