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  • ClF5 Hybridization: A Step-by-Step Guide to Determining Central Atom Geometry
    Here's how to determine the hybridization of the central chlorine atom in ClF5:

    1. Draw the Lewis Structure:

    * Chlorine has 7 valence electrons.

    * Fluorine has 7 valence electrons.

    * There are 5 fluorine atoms, so that's 5 * 7 = 35 valence electrons.

    * Total valence electrons: 7 + 35 = 42

    * Place the chlorine atom in the center.

    * Surround it with 5 fluorine atoms.

    * Fill in the remaining electrons to complete octets around the fluorine atoms.

    * You'll find that the central chlorine atom has 5 bonds (to the fluorine atoms) and one lone pair of electrons.

    2. Count the Steric Number:

    * Steric number = number of atoms bonded to the central atom + number of lone pairs on the central atom.

    * In ClF5, the steric number is 5 + 1 = 6.

    3. Relate Steric Number to Hybridization:

    * Steric number of 6 corresponds to sp³d² hybridization.

    Therefore, the central chlorine atom in ClF5 is sp³d² hybridized.

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