Let's break down this problem step-by-step. It looks like you're dealing with a chemical reaction, but the equation provided is not balanced. Here's how to approach this:

1. Balanced Chemical Equation

The provided equation is not balanced:

2A3 + 3B2 → 6AB

To balance it, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

* A atoms: There are 6 A atoms on the left (2 x 3) and 6 A atoms on the right.

* B atoms: There are 6 B atoms on the left (3 x 2) and 6 B atoms on the right.

The equation is already balanced!

2. Mole Ratio

The balanced equation tells us the mole ratio between reactants and products. From the balanced equation:

* 2 moles of A3 react with 3 moles of B2 to produce 6 moles of AB

3. Limiting Reactant

We are told that 10 moles of A3 are reacted with excess B2. This means that A3 is the limiting reactant. The limiting reactant is the one that gets used up first, determining the amount of product formed.

4. Calculating Moles of AB

Since the mole ratio is 2 moles of A3 : 6 moles of AB, we can set up a proportion:

* 2 moles A3 / 6 moles AB = 10 moles A3 / x moles AB

Solving for x:

* x = (10 moles A3 * 6 moles AB) / 2 moles A3

* x = 30 moles AB

Answer: If 10 moles of A3 are reacted with excess B2, 30 moles of AB will be produced.