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  • Calculate Kw at a Specific Temperature: Understanding Water's Ion Product
    Here's how to determine the value of Kw at that temperature:

    Understanding pH, pOH, and Kw

    * pH: A measure of the acidity or alkalinity of a solution. It's the negative logarithm (base 10) of the hydrogen ion concentration ([H+]).

    * pOH: Similar to pH, but it measures the concentration of hydroxide ions ([OH-]).

    * Kw: The ion product constant for water. It represents the equilibrium constant for the autoionization of water:

    H₂O(l) ⇌ H⁺(aq) + OH⁻(aq)

    Kw = [H⁺][OH⁻]

    Relationship between pH, pOH, and Kw

    * For a neutral solution, [H⁺] = [OH⁻].

    * pH + pOH = 14 (at 25°C)

    * Kw = [H⁺][OH⁻] = 10⁻¹⁴ (at 25°C)

    Solving the Problem

    1. Find pOH: Since the pH is 7.56, we can find the pOH using the relationship:

    pOH = 14 - pH = 14 - 7.56 = 6.44

    2. Calculate [H⁺] and [OH⁻]:

    [H⁺] = 10⁻⁷.⁵⁶

    [OH⁻] = 10⁻⁶.⁴⁴

    3. Determine Kw:

    Kw = [H⁺][OH⁻] = (10⁻⁷.⁵⁶)(10⁻⁶.⁴⁴) = 10⁻¹⁴

    Therefore, the value of Kw at this temperature is 10⁻¹⁴.

    Important Note: While the relationship between pH, pOH, and Kw is usually 14 at 25°C, it changes with temperature. The temperature in this problem isn't specified, so we assume it's a different temperature where the neutral pH is 7.56, but the Kw value remains the same.

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