1. Balanced Chemical Equation:

The balanced chemical equation for the reaction is:

P₄O₁₀ + 6H₂O → 4H₃PO₄

2. Mole Ratio:

From the balanced equation, we see that 6 moles of water (H₂O) react to produce 4 moles of phosphoric acid (H₃PO₄).

3. Calculate Moles of H₃PO₄:

Since we have 10.0 moles of water, we can use the mole ratio to find the moles of H₃PO₄ produced:

(10.0 moles H₂O) * (4 moles H₃PO₄ / 6 moles H₂O) = 6.67 moles H₃PO₄

4. Convert Moles to Grams:

To convert moles of H₃PO₄ to grams, we need its molar mass. The molar mass of H₃PO₄ is:

(3 * 1.01 g/mol H) + (1 * 30.97 g/mol P) + (4 * 16.00 g/mol O) = 98.00 g/mol

Now, multiply the moles of H₃PO₄ by its molar mass:

(6.67 moles H₃PO₄) * (98.00 g/mol H₃PO₄) = 653 g H₃PO₄

Therefore, 653 grams of H₃PO₄ are produced when 10.0 moles of water react with an excess of P₄O₁₀.