The reaction between lead acetate (Pb(CH₃COO)₂) and sodium chloride (NaCl) is a double displacement reaction that results in the formation of lead chloride (PbCl₂) precipitate and sodium acetate (CH₃COONa) in solution.

Here's the balanced chemical equation:

Pb(CH₃COO)₂(aq) + 2NaCl(aq) → PbCl₂(s) + 2CH₃COONa(aq)

Explanation:

* Lead acetate (Pb(CH₃COO)₂) and sodium chloride (NaCl) are both soluble ionic compounds, meaning they dissociate into ions in solution.

* Lead chloride (PbCl₂) is an insoluble ionic compound and therefore precipitates out of solution as a white solid.

* Sodium acetate (CH₃COONa) remains in solution as it is soluble.

Observations:

* When you mix solutions of lead acetate and sodium chloride, a white precipitate (lead chloride) will form immediately.

* The solution will also become slightly acidic due to the presence of acetate ions.

This reaction is commonly used in the lab to demonstrate the formation of a precipitate and the concept of solubility rules.