Here's how to determine the net ionic equation for the reaction of lead(II) nitrate with potassium bromide:

1. Write the balanced molecular equation:

Pb(NO₃)₂(aq) + 2KBr(aq) → PbBr₂(s) + 2KNO₃(aq)

2. Write the complete ionic equation:

Pb²⁺(aq) + 2NO₃⁻(aq) + 2K⁺(aq) + 2Br⁻(aq) → PbBr₂(s) + 2K⁺(aq) + 2NO₃⁻(aq)

3. Identify the spectator ions:

Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are K⁺(aq) and NO₃⁻(aq).

4. Write the net ionic equation by removing the spectator ions:

Pb²⁺(aq) + 2Br⁻(aq) → PbBr₂(s)

Therefore, the net ionic equation for the reaction of lead(II) nitrate with potassium bromide is: Pb²⁺(aq) + 2Br⁻(aq) → PbBr₂(s)