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  • Net Ionic Equation: Silver Acetate & Ammonium Sulfate Reaction
    Here's how to determine the net ionic equation for the reaction between silver acetate (AgC₂H₃O₂) and ammonium sulfate ((NH₄)₂SO₄):

    1. Write the balanced molecular equation:

    2 AgC₂H₃O₂(aq) + (NH₄)₂SO₄(aq) → Ag₂SO₄(s) + 2 NH₄C₂H₃O₂(aq)

    2. Write the complete ionic equation:

    This involves breaking down all soluble ionic compounds into their respective ions:

    2 Ag⁺(aq) + 2 C₂H₃O₂⁻(aq) + 2 NH₄⁺(aq) + SO₄²⁻(aq) → Ag₂SO₄(s) + 2 NH₄⁺(aq) + 2 C₂H₃O₂⁻(aq)

    3. Identify and cancel spectator ions:

    Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are NH₄⁺ and C₂H₃O₂⁻.

    4. Write the net ionic equation:

    This includes only the ions that directly participate in the reaction:

    2 Ag⁺(aq) + SO₄²⁻(aq) → Ag₂SO₄(s)

    Therefore, the net ionic equation for the reaction between silver acetate and ammonium sulfate is:

    2 Ag⁺(aq) + SO₄²⁻(aq) → Ag₂SO₄(s)

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