1. Calculate the molar mass of silver nitrate:
* Ag: 107.87 g/mol
* N: 14.01 g/mol
* O: 16.00 g/mol (x3 for three oxygen atoms)
* Total molar mass: 107.87 + 14.01 + (16.00 x 3) = 169.88 g/mol
2. Calculate the number of moles of silver nitrate:
* Moles = Mass / Molar mass
* Moles = 65 g / 169.88 g/mol
* Moles ≈ 0.383 moles
3. Convert moles to molecules using Avogadro's number:
* Avogadro's number: 6.022 x 10²³ molecules/mol
* Number of molecules = Moles x Avogadro's number
* Number of molecules ≈ 0.383 moles x 6.022 x 10²³ molecules/mol
* Number of molecules ≈ 2.30 x 10²³ molecules
Therefore, there are approximately 2.30 x 10²³ molecules in 65 g of silver nitrate.
