1. Write the balanced chemical equation:

AgNO₃(aq) + HCl(aq) → AgCl(s) + HNO₃(aq)

2. Determine the moles of AgNO₃:

* Molarity (M) = moles (mol) / volume (L)

* 0.068 M = moles / 0.025 L

* moles of AgNO₃ = 0.0017 mol

3. Use the mole ratio from the balanced equation to find moles of AgCl:

* The balanced equation shows a 1:1 mole ratio between AgNO₃ and AgCl. Therefore, 0.0017 moles of AgNO₃ will produce 0.0017 moles of AgCl.

4. Calculate the mass of AgCl:

* Molar mass of AgCl = 143.32 g/mol

* mass = moles x molar mass

* mass of AgCl = 0.0017 mol x 143.32 g/mol

* mass of AgCl = 0.244 g

Therefore, 0.244 g of solid AgCl is obtained.