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  • Nitrogen Molecule Calculation: Number of Molecules in 1.00L at 1 atm & 298K
    Here's how to calculate the number of nitrogen molecules (N₂) in 1.00 L of gas at atmospheric pressure (1 atm) and 298 K:

    1. Use the Ideal Gas Law:

    The ideal gas law states: PV = nRT

    Where:

    * P = Pressure (atm)

    * V = Volume (L)

    * n = Number of moles

    * R = Ideal gas constant (0.0821 L·atm/mol·K)

    * T = Temperature (K)

    2. Solve for the number of moles (n):

    * n = PV / RT

    * n = (1 atm * 1.00 L) / (0.0821 L·atm/mol·K * 298 K)

    * n ≈ 0.0409 moles

    3. Convert moles to molecules:

    * Avogadro's number tells us that 1 mole contains 6.022 x 10²³ molecules.

    * Number of molecules = n * Avogadro's number

    * Number of molecules ≈ 0.0409 moles * 6.022 x 10²³ molecules/mole

    * Number of molecules ≈ 2.46 x 10²² molecules

    Therefore, there are approximately 2.46 x 10²² nitrogen molecules in 1.00 L of gas at 1 atm and 298 K.

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