1. Calculate the moles of KI:
* Molar mass of KI:
* K (potassium) = 39.10 g/mol
* I (iodine) = 126.90 g/mol
* Total molar mass = 39.10 + 126.90 = 166.00 g/mol
* Moles of KI:
* moles = mass / molar mass
* moles = 2.41 g / 166.00 g/mol = 0.0145 mol
2. Convert volume to liters:
* Volume in liters: 100 mL = 0.100 L
3. Calculate molarity:
* Molarity (M) = moles of solute / liters of solution
* Molarity = 0.0145 mol / 0.100 L = 0.145 M
Therefore, the molarity of the potassium iodide solution is 0.145 M.
