1. Determine the Molecular Weight of Iodine (I₂)
* The atomic weight of iodine is 126.90 g/mol.
* Since iodine exists as a diatomic molecule (I₂), the molecular weight is 2 * 126.90 g/mol = 253.80 g/mol.
2. Calculate the Moles of Iodine
* Divide the mass of iodine by its molecular weight:
* Moles of I₂ = 4.65 g / 253.80 g/mol = 0.0183 mol
3. Convert Volume to Liters
* 235 mL = 0.235 L
4. Calculate Molarity
* Molarity (M) = Moles of solute / Volume of solution in liters
* M = 0.0183 mol / 0.235 L = 0.0779 M
Therefore, the molarity of the alcoholic iodine solution is approximately 0.0779 M.
