• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Single Displacement Reaction: Chlorine Gas & Sodium Iodide
    The reaction you're describing is a single displacement reaction. Here's why:

    * Single Displacement: In this type of reaction, a more reactive element displaces a less reactive element from its compound.

    * The Reaction: Chlorine (Cl₂) is more reactive than iodine (I₂). When chlorine gas is bubbled through a solution of sodium iodide (NaI), the chlorine atoms displace the iodine atoms from the iodide ions (I⁻).

    The Chemical Equation:

    Cl₂(g) + 2NaI(aq) → 2NaCl(aq) + I₂(s)

    * Reactants: Chlorine gas (Cl₂) and sodium iodide (NaI)

    * Products: Sodium chloride (NaCl) and elemental iodine (I₂)

    Explanation:

    * Chlorine (Cl₂) is a stronger oxidizing agent than iodine (I₂). This means it has a greater tendency to gain electrons.

    * Chlorine atoms react with iodide ions (I⁻) to form chloride ions (Cl⁻) and elemental iodine (I₂).

    * The iodine atoms then combine to form diatomic iodine molecules (I₂), which are insoluble in water and precipitate out as a solid.

    Key Points:

    * The reaction is driven by the difference in reactivity between chlorine and iodine.

    * The reaction produces a color change, as the colorless solution turns brown due to the formation of elemental iodine.

    Science Discoveries © www.scienceaq.com