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  • Iron(II) Sulfate and Sodium Hydroxide Reaction: Products and Aqueous Solution
    Here's the breakdown of the reaction between iron(II) sulfate solution and sodium hydroxide:

    The Reaction

    Iron(II) sulfate (FeSO₄) reacts with sodium hydroxide (NaOH) in an aqueous solution to form a green precipitate of iron(II) hydroxide (Fe(OH)₂) and a solution of sodium sulfate (Na₂SO₄).

    Chemical Equation:

    FeSO₄(aq) + 2NaOH(aq) → Fe(OH)₂(s) + Na₂SO₄(aq)

    Explanation:

    * Iron(II) sulfate (FeSO₄) is a soluble ionic compound that dissolves in water to form Fe²⁺ and SO₄²⁻ ions.

    * Sodium hydroxide (NaOH) is also a soluble ionic compound that dissolves in water to form Na⁺ and OH⁻ ions.

    * Iron(II) hydroxide (Fe(OH)₂) is an insoluble ionic compound that forms a green precipitate.

    * Sodium sulfate (Na₂SO₄) is a soluble ionic compound that remains dissolved in the solution.

    Aqueous Products:

    Yes, sodium sulfate (Na₂SO₄) is the aqueous product of this reaction. It remains dissolved in the solution.

    Key Points

    * The reaction is a double displacement reaction.

    * The formation of the precipitate (Fe(OH)₂) is a key indicator that the reaction has occurred.

    * The precipitate can be separated from the solution by filtration.

    Let me know if you'd like more details on any aspect of this reaction!

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