• Home
  • Chemistry
  • Astronomy
  • Energy
  • Nature
  • Biology
  • Physics
  • Electronics
  • Silver Nitrate and Sodium Phosphate Reaction: Mole Ratio Calculation
    Here's how to solve this problem:

    1. Write the balanced chemical equation:

    3 AgNO₃ (aq) + Na₃PO₄ (aq) → Ag₃PO₄ (s) + 3 NaNO₃ (aq)

    2. Determine the mole ratio from the balanced equation:

    The equation shows that 3 moles of silver nitrate (AgNO₃) react with 1 mole of sodium phosphate (Na₃PO₄).

    3. Calculate the moles of silver nitrate:

    Since you have 2.00 moles of sodium phosphate, you'll need three times that amount of silver nitrate:

    Moles of AgNO₃ = 2.00 moles Na₃PO₄ × (3 moles AgNO₃ / 1 mole Na₃PO₄) = 6.00 moles AgNO₃

    Therefore, you would need 6.00 moles of silver nitrate to react with 2.00 moles of sodium phosphate.

    Science Discoveries © www.scienceaq.com