Ferric chloride (FeCl₃) reacts with potassium iodide (KI) solution in a redox reaction to produce iodine (I₂), potassium chloride (KCl), and ferrous chloride (FeCl₂).

Here's the balanced chemical equation for the reaction:

2 FeCl₃(aq) + 2 KI(aq) → 2 FeCl₂(aq) + 2 KCl(aq) + I₂(aq)

Here's a breakdown of the reaction:

* Oxidation: Iodide ions (I⁻) from potassium iodide are oxidized to iodine (I₂) by losing electrons.

* Reduction: Ferric ions (Fe³⁺) from ferric chloride are reduced to ferrous ions (Fe²⁺) by gaining electrons.

Observations:

* You'll observe a color change from the initial yellowish-brown solution of ferric chloride to a brown solution due to the formation of iodine.

* The solution might also turn cloudy as iodine is slightly soluble in water.

* If the reaction is carried out in a test tube, you might see purple vapor rising from the solution, indicating the presence of iodine.

Additional Notes:

* The reaction is quite rapid and can be used as a qualitative test for the presence of ferric ions.

* The reaction is also used in the production of iodine.

* The reaction is exothermic, meaning it releases heat.

Let me know if you'd like to know more about any of the products or aspects of the reaction!