1. Find the molar mass of Bismuth:
* The molar mass of Bismuth is approximately 208.98 g/mol.
2. Calculate the number of moles:
* Divide the mass of Bismuth by its molar mass:
* moles of Bi = 1.84 g / 208.98 g/mol ≈ 0.0088 mol
3. Use Avogadro's number:
* Avogadro's number states that there are 6.022 x 10^23 atoms in one mole of any substance.
* Multiply the number of moles by Avogadro's number:
* atoms of Bi = 0.0088 mol * 6.022 x 10^23 atoms/mol ≈ 5.3 x 10^21 atoms
Therefore, there are approximately 5.3 x 10^21 atoms in 1.84 g of Bismuth.
