The Reaction
Copper sulfate (CuSO₄) is a blue crystalline solid, and iron (Fe) is a metallic element. When these two substances are mixed in an aqueous solution (water), a single displacement reaction occurs.
Here's the chemical equation for the reaction:
CuSO₄ (aq) + Fe (s) → FeSO₄ (aq) + Cu (s)
What happens to the particles:
1. Iron (Fe) atoms: Iron atoms are more reactive than copper atoms. When iron is introduced to the copper sulfate solution, the iron atoms lose electrons (oxidation) and become iron(II) ions (Fe²⁺).
2. Copper(II) ions (Cu²⁺): Copper(II) ions in the copper sulfate solution gain electrons (reduction) and become copper atoms (Cu).
3. Sulfate ions (SO₄²⁻): Sulfate ions remain unchanged throughout the reaction. They are spectator ions, meaning they are present in the solution but don't directly participate in the chemical change.
The Result
* Iron sulfate (FeSO₄) forms in the solution. Iron sulfate is usually a greenish-blue color.
* Copper (Cu) is deposited as a reddish-brown solid. You'll observe this as a coating or sediment forming in the reaction vessel.
Particle level explanation:
* At the atomic level, iron atoms donate electrons to copper(II) ions.
* This electron transfer causes the iron atoms to become positively charged ions (Fe²⁺) and the copper(II) ions to become neutral copper atoms (Cu).
Key Points
* The reaction is a single displacement reaction where a more reactive metal (iron) displaces a less reactive metal (copper) from its salt solution.
* The reaction involves the transfer of electrons (oxidation-reduction), leading to the formation of new compounds.
Let me know if you have any other questions!
