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  • Balanced Chemical Equation for Octadecane Combustion (C18H38)
    The balanced chemical equation for burning C18H38 (octadecane) in air is:

    2 C18H38 + 55 O2 → 36 CO2 + 38 H2O

    Here's how to break it down:

    * C18H38: This is the formula for octadecane, a type of alkane.

    * O2: This is the formula for oxygen, which is present in the air.

    * CO2: This is the formula for carbon dioxide, a product of combustion.

    * H2O: This is the formula for water, another product of combustion.

    Balancing the equation:

    * Carbon (C): There are 18 carbon atoms on the left side and 36 on the right. We need to multiply the CO2 by 2.

    * Hydrogen (H): There are 38 hydrogen atoms on the left side and 38 on the right. The equation is already balanced for hydrogen.

    * Oxygen (O): There are 55 oxygen atoms on the right side and 2 on the left. We need to multiply the O2 by 55/2, which simplifies to 27.5. However, we cannot have fractions in a chemical equation. Therefore, we multiply the entire equation by 2 to get whole numbers.

    This process leads to the final balanced equation:

    2 C18H38 + 55 O2 → 36 CO2 + 38 H2O

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