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  • Acetone Oxidation with Potassium Dichromate: Equation & Explanation
    The reaction of acetone (propanone) with acidified potassium dichromate is an oxidation reaction. Here's the balanced chemical equation:

    3 CH₃COCH₃ (acetone) + 4 K₂Cr₂O₇ (potassium dichromate) + 16 H₂SO₄ (sulfuric acid) → 3 CH₃COOH (acetic acid) + 4 Cr₂(SO₄)₃ (chromium(III) sulfate) + 4 K₂SO₄ (potassium sulfate) + 16 H₂O (water)

    Here's a breakdown of the reaction:

    * Acetone (CH₃COCH₃): The reactant being oxidized. It contains a secondary alcohol functional group.

    * Potassium dichromate (K₂Cr₂O₇): The oxidizing agent. It contains chromium(VI) ions, which are reduced during the reaction.

    * Sulfuric acid (H₂SO₄): Provides the acidic environment needed for the reaction to occur.

    * Acetic acid (CH₃COOH): The product formed by the oxidation of acetone.

    * Chromium(III) sulfate (Cr₂(SO₄)₃): The product formed by the reduction of potassium dichromate.

    * Potassium sulfate (K₂SO₄): Another product formed.

    * Water (H₂O): A by-product of the reaction.

    Important Notes:

    * This reaction is typically carried out under reflux conditions.

    * The reaction is exothermic and can be quite vigorous.

    * The color change from orange (dichromate) to green (chromium(III) ions) is a good indicator of the reaction taking place.

    Let me know if you have any other questions!

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