1. Write the balanced chemical equation:

The reaction of sodium (Na) with oxygen (O₂) produces sodium oxide (Na₂O):

4 Na + O₂ → 2 Na₂O

2. Determine the molar mass of sodium oxide (Na₂O):

* Na: 22.99 g/mol

* O: 16.00 g/mol

Molar mass of Na₂O = (2 * 22.99 g/mol) + (1 * 16.00 g/mol) = 61.98 g/mol

3. Calculate the moles of sodium oxide:

* Moles = mass / molar mass

* Moles of Na₂O = 108.2 g / 61.98 g/mol = 1.746 mol

4. Use the mole ratio from the balanced equation to find the moles of sodium:

From the balanced equation, we see that 4 moles of Na react to produce 2 moles of Na₂O. Therefore, the mole ratio is 4:2, or 2:1.

* Moles of Na = (2/1) * 1.746 mol = 3.492 mol

5. Calculate the mass of sodium:

* Mass = moles * molar mass

* Mass of Na = 3.492 mol * 22.99 g/mol = 80.3 g

Therefore, you need 80.3 g of sodium to produce 108.2 g of sodium oxide.