The balanced equation for the decomposition of lead(IV) oxide (PbO₂) is:

2PbO₂ → 2PbO + O₂

Here's what the equation represents:

* PbO₂: Lead(IV) oxide, the reactant.

* PbO: Lead(II) oxide, one of the products.

* O₂: Oxygen gas, the other product.

Explanation:

When lead(IV) oxide is heated, it decomposes into lead(II) oxide and oxygen gas. This is a redox reaction where lead is reduced from +4 oxidation state in PbO₂ to +2 oxidation state in PbO, while oxygen is oxidized from -2 in PbO₂ to 0 in O₂.