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  • Oxidation Number of Cl in HClO4: A Step-by-Step Guide
    Here's how to determine the oxidation number of chlorine (Cl) in HClO4:

    Rules to Remember:

    * Oxygen (O): Usually has an oxidation number of -2, except in peroxides (like H2O2) where it is -1.

    * Hydrogen (H): Usually has an oxidation number of +1, except in metal hydrides (like LiH) where it is -1.

    * The sum of oxidation numbers in a neutral compound is zero.

    * The sum of oxidation numbers in a polyatomic ion equals the charge of the ion.

    Applying the Rules to HClO4:

    1. Oxygen (O): There are four oxygen atoms, each with an oxidation number of -2, for a total of -8.

    2. Hydrogen (H): There is one hydrogen atom with an oxidation number of +1.

    3. Chlorine (Cl): Let the oxidation number of chlorine be 'x'.

    4. Sum: The sum of the oxidation numbers must equal zero since HClO4 is a neutral compound: x + (+1) + (-8) = 0

    5. Solving for x: x - 7 = 0

    Therefore, x = +7

    Therefore, the oxidation number of chlorine (Cl) in HClO4 is +7.

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