1. Balanced Chemical Equation:

First, write the balanced chemical equation for the reaction:

2 AgNO₃ (aq) + Na₂CrO₄ (aq) → Ag₂CrO₄ (s) + 2 NaNO₃ (aq)

2. Mole Ratio:

The balanced equation shows that 2 moles of silver nitrate (AgNO₃) react to produce 1 mole of silver chromate (Ag₂CrO₄). This is the mole ratio we'll use.

3. Calculation:

* Start with the given moles of silver nitrate (AgNO₃): 4 moles AgNO₃

* Use the mole ratio to convert moles of AgNO₃ to moles of Ag₂CrO₄:

(4 moles AgNO₃) * (1 mole Ag₂CrO₄ / 2 moles AgNO₃) = 2 moles Ag₂CrO₄

Answer: 4 moles of silver nitrate (AgNO₃) will produce 2 moles of silver chromate (Ag₂CrO₄).