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  • Predicting Products of Lead(IV) Sulfate and Tin(II) Chlorate Reaction
    Here's how to determine the products of the reaction between lead(IV) sulfate and tin(II) chlorate:

    1. Write the Chemical Formulas:

    * Lead(IV) sulfate: Pb(SO₄)₂

    * Tin(II) chlorate: Sn(ClO₃)₂

    2. Identify the Ions Involved:

    * Lead(IV) sulfate dissociates into Pb⁴⁺ and SO₄²⁻ ions.

    * Tin(II) chlorate dissociates into Sn²⁺ and ClO₃⁻ ions.

    3. Predict the Products Using a Double Displacement Reaction:

    In a double displacement reaction, the positive ions (cations) switch partners. This means:

    * Pb⁴⁺ will combine with ClO₃⁻ to form lead(IV) chlorate (Pb(ClO₃)₄).

    * Sn²⁺ will combine with SO₄²⁻ to form tin(II) sulfate (SnSO₄).

    4. Balance the Chemical Equation:

    The balanced chemical equation for this reaction is:

    Pb(SO₄)₂ + 2 Sn(ClO₃)₂ → Pb(ClO₃)₄ + 2 SnSO₄

    Therefore, the newly formed compounds are lead(IV) chlorate (Pb(ClO₃)₄) and tin(II) sulfate (SnSO₄).

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