* Formation of an ionic bond: Potassium (K) is an alkali metal, meaning it has one valence electron it readily loses to achieve a stable electron configuration. Bromine (Br) is a halogen and needs one electron to complete its outer shell.
* Transfer of electrons: The potassium atom will donate its valence electron to the bromine atom.
* Formation of ions: The potassium atom becomes a positively charged potassium ion (K+), while the bromine atom becomes a negatively charged bromide ion (Br-).
* Ionic compound formation: The oppositely charged ions attract each other electrostatically and form an ionic bond, resulting in the formation of potassium bromide (KBr).
The reaction can be represented as:
K + Br → K+ + Br- → KBr
In summary: The reaction between potassium and bromine results in the formation of an ionic compound, potassium bromide, through the transfer of an electron from the potassium atom to the bromine atom.