1. Determine the molar mass of NaOH:
* Na: 22.99 g/mol
* O: 16.00 g/mol
* H: 1.01 g/mol
* Total molar mass: 22.99 + 16.00 + 1.01 = 40.00 g/mol
2. Calculate the moles of NaOH needed:
* Molarity (M) = moles of solute / liters of solution
* We have 0.10 M and 100 mL (which is 0.100 L)
* Rearranging the equation: moles of solute = Molarity * Liters of solution
* moles of NaOH = 0.10 M * 0.100 L = 0.010 moles
3. Calculate the mass of NaOH:
* mass = moles * molar mass
* mass of NaOH = 0.010 moles * 40.00 g/mol = 0.40 g
Therefore, you would need 0.40 grams of sodium hydroxide to prepare 100 mL of a 0.10 M solution.
Important Note: Always handle sodium hydroxide with care as it is a strong base. Wear appropriate safety gear and work in a well-ventilated area.
