The reaction is:
2 LiI(aq) + Cl₂(g) → 2 LiCl(aq) + I₂(s)
Here's what happens:
* Chlorine (Cl₂) is a strong oxidizing agent and is more reactive than iodine.
* Lithium iodide (LiI) is a salt containing iodide ions (I⁻).
* Chlorine displaces the iodide ions (I⁻), forming lithium chloride (LiCl) and elemental iodine (I₂).
* Elemental iodine (I₂) is a solid, typically a dark purple or grayish-black color.
Important Note: This reaction is exothermic, meaning it releases heat.
Safety: Chlorine gas is toxic, and iodine vapor can irritate the respiratory system. This reaction should be performed in a well-ventilated area with appropriate safety precautions.