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  • Iodine Production from Fluorine and Potassium Iodide: A Step-by-Step Calculation
    Here's how to solve this problem:

    1. Balanced Chemical Equation:

    The balanced chemical equation for the reaction is:

    2 KI + F₂ → 2 KF + I₂

    2. Mole Ratio:

    From the balanced equation, we see that 1 mole of F₂ reacts to produce 1 mole of I₂.

    3. Calculate Moles of Iodine:

    Since the mole ratio is 1:1, 0.72 moles of F₂ will produce 0.72 moles of I₂.

    4. Convert Moles to Grams:

    * The molar mass of iodine (I₂) is 253.8 g/mol.

    * Grams of I₂ = moles of I₂ × molar mass of I₂

    * Grams of I₂ = 0.72 mol × 253.8 g/mol

    * Grams of I₂ = 182.7 g

    Therefore, 182.7 grams of iodine are produced when 0.72 mol of fluorine reacts with potassium iodide.

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