Here's how to predict the shape of carbon tetraiodide (CI₄) using VSEPR theory:

1. Lewis Structure:

* Carbon (C) has 4 valence electrons.

* Iodine (I) has 7 valence electrons.

To achieve a stable octet, carbon forms four single bonds with four iodine atoms. The Lewis structure looks like this:

I

|

I - C - I

|

I

2. Electron Domain Geometry:

* Central atom: Carbon

* Number of electron domains around central atom: 4 (each single bond represents one electron domain)

According to VSEPR theory, 4 electron domains around a central atom lead to a tetrahedral electron domain geometry.

3. Molecular Geometry:

* Since all four electron domains are bonding pairs (single bonds), the molecular geometry is the same as the electron domain geometry: tetrahedral.

Therefore, the shape of carbon tetraiodide (CI₄) is tetrahedral.