HOOC-CH2-CH(OH)-COOH (Malic Acid) + 2 NaOH (Sodium Hydroxide) → NaOOC-CH2-CH(OH)-COONa (Sodium Malate) + 2 H2O (Water)
Let me break down the equation:
* Malic Acid (HOOC-CH2-CH(OH)-COOH): Malic acid is a dicarboxylic acid, meaning it has two carboxyl groups (COOH) that can donate protons (H+).
* Sodium Hydroxide (NaOH): Sodium hydroxide is a strong base and provides hydroxide ions (OH-) which can accept protons.
* Sodium Malate (NaOOC-CH2-CH(OH)-COONa): This is the salt formed when the protons from the malic acid are replaced by sodium ions (Na+).
* Water (H2O): Water is formed as a byproduct of the proton transfer from the acid to the base.
Important Note: This reaction occurs in two steps, as each carboxyl group in malic acid reacts with one molecule of sodium hydroxide.
