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  • Net Ionic Equation for NaCl and Hg(NO₃)₂ Reaction - Chemistry Explained
    Here's how to determine the net ionic equation for the reaction of aqueous sodium chloride (NaCl) with mercury(II) nitrate (Hg(NO₃)₂) :

    1. Write the Balanced Molecular Equation:

    The reactants are NaCl (aq) and Hg(NO₃)₂ (aq). The products are HgCl₂ (s) (mercury(II) chloride is insoluble) and NaNO₃ (aq).

    The balanced molecular equation is:

    2 NaCl (aq) + Hg(NO₃)₂ (aq) → HgCl₂ (s) + 2 NaNO₃ (aq)

    2. Write the Complete Ionic Equation:

    Break down all soluble ionic compounds into their ions:

    2 Na⁺ (aq) + 2 Cl⁻ (aq) + Hg²⁺ (aq) + 2 NO₃⁻ (aq) → HgCl₂ (s) + 2 Na⁺ (aq) + 2 NO₃⁻ (aq)

    3. Identify Spectator Ions:

    Spectator ions are ions that appear on both sides of the equation and do not participate in the reaction. In this case, the spectator ions are Na⁺ and NO₃⁻.

    4. Write the Net Ionic Equation:

    Cancel out the spectator ions from the complete ionic equation:

    2 Cl⁻ (aq) + Hg²⁺ (aq) → HgCl₂ (s)

    Therefore, the net ionic equation for the reaction of aqueous sodium chloride with mercury nitrate is:

    2 Cl⁻ (aq) + Hg²⁺ (aq) → HgCl₂ (s)

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